Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 21:23Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
132K
e^{i\pi} + 1 = 0
∫₀^∞ e^(-n²) dn = √π / 2
97K
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
52K
det| 4 1 ; 1 5 | = 19
CH₄ + 2O₂ → CO₂ + 2H₂O
346K
det| 9 5 ; 5 10 | = 65
∑_{k=1}^{n} k = n(n+1)/2
130K
det| 9 4 ; 1 10 | = 86
82K
d/dθ [θ^5] = 5θ^4
∑_{k=1}^{n} k = n(n+1)/2
3K
∇²x = 0
e^{i\pi} + 1 = 0
e^{i\pi} + 1 = 0