Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 23:32Z
\frac{2}{6} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
212K
F = ma
det| 9 4 ; 1 10 | = 86
102K
∑_{k=1}^{n} k = n(n+1)/2
217K
2γ² + 2γ + 5 = 0
∫₀^∞ e^(-β²) dβ = √π / 2
280K
∑_{k=1}^{n} k = n(n+1)/2
323K
∑_{k=1}^{n} k = n(n+1)/2