Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
75K
det| 9 7 ; 3 10 | = 69
132K
2y² + 6y + 4 = 0
det| 4 7 ; 2 5 | = 6
170K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 10 7 ; 3 11 | = 89
344K
2y² + 4y + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
393K