Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:39Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
97K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 9 ; 5 10 | = 45
52K
2y² + 4y + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
82K
\oint_C \vec{F}\cdot d\vec{r} = 0
3K