Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 04:53Z
2ψ² + 8ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 5 9 ; 7 6 | = -33
132K
∂y/∂ψ = 5y
det| 7 4 ; 4 8 | = 40
97K
e^{i\pi} + 1 = 0
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
d/dz [z^10] = 10z^9