Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 05:37Z
det| 3 2 ; 6 4 | = 0
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 7 4 ; 4 8 | = 40
132K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
170K
det| 6 9 ; 7 7 | = -21
det| 3 1 ; 7 4 | = 5
344K
∑_{k=1}^{n} k = n(n+1)/2
ΔS ≥ 0
det| 12 2 ; 2 13 | = 152
130K
∑_{k=1}^{n} k = n(n+1)/2
82K
5ω² + 4ω + 4 = 0
e^{i\pi} + 1 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2