Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 01:33Z
e^{i\pi} + 1 = 0
det| 2 4 ; 4 3 | = -10
327K
∑_{k=1}^{n} k = n(n+1)/2
det| 8 4 ; 6 9 | = 48
59K
3y² + 6y + 5 = 0
∫₀^∞ e^(-z²) dz = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
112K
∑_{k=1}^{n} k = n(n+1)/2
2K