Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 20:26Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{11}{9} \sum_{i=1}^{n} i^{2}
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det| 9 4 ; 1 10 | = 86
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
d/dβ [β^5] = 5β^4
det| 2 4 ; 4 3 | = -10
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 4 5 ; 2 5 | = 10
∫₀^∞ e^(-n²) dn = √π / 2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∑_{k=1}^{n} k = n(n+1)/2
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