Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 05:37Z
det| 3 2 ; 6 4 | = 0
ω = 2πf
det| 5 9 ; 7 6 | = -33
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det| 6 9 ; 7 7 | = -21
∫₀^∞ e^(-ω²) dω = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
det| 5 3 ; 2 6 | = 24
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∑_{k=1}^{n} k = n(n+1)/2
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ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O