Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:23Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
170K
∑_{k=1}^{n} k = n(n+1)/2
97K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 6 6 ; 2 7 | = 30
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2y² + 4y + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
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det| 1 4 ; 0 2 | = 2
130K