Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
\frac{7}{1} \sum_{i=1}^{n} i^{2}
97K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
52K
2y² + 4y + 4 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 4 ; 1 10 | = 86
82K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
3K
∑_{k=1}^{n} k = n(n+1)/2
391K