Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 23:56Z
∇²x = 0
∑_{k=1}^{n} k = n(n+1)/2
132K
7β² + 4β + 7 = 0
E = mc²
det| 7 4 ; 4 8 | = 40
52K
2r² + 4r + 7 = 0
det| 9 9 ; 5 10 | = 45
393K
∑_{k=1}^{n} k = n(n+1)/2
346K
det| 1 1 ; 3 2 | = -1
130K