Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
det| 3 1 ; 7 4 | = 5
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
2y² + 4y + 4 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
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∫₀^∞ e^(-n²) dn = √π / 2
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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