Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 21:07Z
N₂ + 3H₂ ⇌ 2NH₃
det| 7 4 ; 4 8 | = 40
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e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∑_{k=1}^{n} k = n(n+1)/2
344K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
393K