Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 04:50Z
2ψ² + 8ψ + 4 = 0
det| 4 8 ; 0 5 | = 20
75K
∫₀^∞ e^(-β²) dβ = √π / 2
132K
∂y/∂ψ = 5y
∑_{k=1}^{n} k = n(n+1)/2
170K
det| 9 4 ; 1 10 | = 86
97K
e^{i\pi} + 1 = 0
det| 3 1 ; 7 4 | = 5
344K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
d/dz [z^10] = 10z^9
det| 7 4 ; 1 8 | = 52
det| 4 4 ; 7 5 | = -8
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2