Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 16:38Z
10y² + 5y + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
232K
8t² + 6t + 7 = 0
d/dω [ω^5] = 5ω^4
det| 9 6 ; 7 10 | = 48
435K
det| 9 4 ; 1 10 | = 86
84K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
7t² + 2t + 3 = 0