Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 17:54Z
8φ² + 9φ + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
212K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
347K
ΔS ≥ 0
\frac{12}{7} \sum_{i=1}^{n} i^{2}
102K
\frac{6}{7} \sum_{i=1}^{n} i^{2}
217K
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
323K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-ω²) dω = √π / 2
62K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
239K