Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 23:07Z
\frac{2}{6} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
212K
det| 5 6 ; 1 6 | = 24
347K
F = ma
det| 7 4 ; 4 8 | = 40
102K
2γ² + 2γ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
62K