Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 16:39Z
10y² + 5y + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 4 ; 1 10 | = 86
59K
8t² + 6t + 7 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
23K
det| 10 2 ; 1 11 | = 108
459K
d/dω [ω^5] = 5ω^4
ΔS ≥ 0
\oint_C \vec{F}\cdot d\vec{r} = 0
323K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
112K
7t² + 2t + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O