Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 02:51Z
2t² + 6t + 4 = 0
∫₀^∞ e^(-n²) dn = √π / 2
212K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 7 4 ; 4 8 | = 40
102K
det| 9 7 ; 0 10 | = 90
Fe₂O₃ + 3CO → 2Fe + 3CO₂
323K
∫₀^∞ e^(-t²) dt = √π / 2
239K