Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 19:43Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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F = ma
\oint_C \vec{F}\cdot d\vec{r} = 0
∫₀^∞ e^(-β²) dβ = √π / 2
52K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∂y/∂β = 3y
9n² + 3n + 4 = 0
10φ² + 9φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O