Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:37Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-β²) dβ = √π / 2
344K
2y² + 4y + 4 = 0
det| 5 3 ; 2 6 | = 24
393K
det| 3 7 ; 2 4 | = -2
346K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 9 ; 6 8 | = 2