Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 18:19Z
det| 5 5 ; 5 6 | = 5
∫₀^∞ e^(-β²) dβ = √π / 2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 5 6 ; 1 6 | = 24
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\lim_{x\to 0} \frac{\sin x}{x} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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λ = h/p
det| 6 6 ; 5 7 | = 12
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\lim_{β\to 0} \frac{\sin β}{β} = 1
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