Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 12:28Z
∑_{k=1}^{n} k = n(n+1)/2
2ω² + 3ω + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
232K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
23K
det| 9 4 ; 1 10 | = 86
459K
det| 1 1 ; 3 2 | = -1
e^{i\pi} + 1 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
2K