Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 01:52Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
232K
3y² + 6y + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
459K
∫₀^∞ e^(-z²) dz = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
d/dx [x^9] = 9x^8
e^{i\pi} + 1 = 0
det| 12 2 ; 0 13 | = 156
ω = 2πf