Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 01:33Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
59K
3y² + 6y + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
23K
∑_{k=1}^{n} k = n(n+1)/2
459K
∫₀^∞ e^(-z²) dz = √π / 2
det| 9 6 ; 7 10 | = 48
435K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
d/dx [x^9] = 9x^8
e^{i\pi} + 1 = 0