Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:09Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
132K
2y² + 6y + 4 = 0
det| 7 4 ; 4 8 | = 40
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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det| 7 8 ; 6 8 | = 8
393K
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-ω²) dω = √π / 2
3K
det| 3 7 ; 2 4 | = -2
391K