Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:23Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
75K
2y² + 6y + 4 = 0
det| 11 9 ; 0 12 | = 132
170K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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2y² + 4y + 4 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
393K
\lim_{y\to 0} \frac{\sin y}{y} = 1
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\lim_{β\to 0} \frac{\sin β}{β} = 1
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