Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:23Z
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 1 6 | = 24
75K
2y² + 6y + 4 = 0
det| 5 3 ; 2 6 | = 24
170K
det| 7 4 ; 4 8 | = 40
97K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
2y² + 4y + 4 = 0
∫₀^∞ e^(-n²) dn = √π / 2
346K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
130K
∑_{k=1}^{n} k = n(n+1)/2
3K