Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:23Z
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
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2y² + 6y + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-φ²) dφ = √π / 2
52K
2y² + 4y + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
393K
det| 7 4 ; 4 8 | = 40
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