Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-z²) dz = √π / 2
132K
2y² + 6y + 4 = 0
det| 7 4 ; 4 8 | = 40
170K
∑_{k=1}^{n} k = n(n+1)/2
97K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 7 ; 3 10 | = 69
344K
2y² + 4y + 4 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
130K
∑_{k=1}^{n} k = n(n+1)/2
3K