Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 04:44Z
2ψ² + 8ψ + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
132K
∂y/∂ψ = 5y
∑_{k=1}^{n} k = n(n+1)/2
170K
e^{i\pi} + 1 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
52K
∇ × E = −∂B/∂t
det| 9 4 ; 1 10 | = 86
393K
∑_{k=1}^{n} k = n(n+1)/2
d/dz [z^10] = 10z^9
det| 7 4 ; 1 8 | = 52
det| 4 4 ; 7 5 | = -8
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2