Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 20:40Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-β²) dβ = √π / 2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
d/dβ [β^5] = 5β^4
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 4 5 ; 2 5 | = 10
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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