Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 8 ; 3 10 | = 66
132K
2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 11 9 ; 5 12 | = 87
52K
∑_{k=1}^{n} k = n(n+1)/2
130K
∫₀^∞ e^(-t²) dt = √π / 2
82K