Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:23Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
52K
2y² + 4y + 4 = 0
det| 10 3 ; 4 11 | = 98
393K
CH₄ + 2O₂ → CO₂ + 2H₂O
130K
∑_{k=1}^{n} k = n(n+1)/2
3K