Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 05:39Z
det| 3 2 ; 6 4 | = 0
ω = 2πf
det| 9 4 ; 1 10 | = 86
170K
∫₀^∞ e^(-β²) dβ = √π / 2
97K
det| 6 9 ; 7 7 | = -21
det| 9 8 ; 3 10 | = 66
344K
∑_{k=1}^{n} k = n(n+1)/2
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
5ω² + 4ω + 4 = 0