Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 19:44Z
∑_{k=1}^{n} k = n(n+1)/2
det| 1 1 ; 3 2 | = -1
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det| 7 6 ; 1 8 | = 50
det| 11 9 ; 0 12 | = 132
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d/dn [n^9] = 9n^8
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
det| 9 9 ; 5 10 | = 45
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