Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 17:18Z
F = ma
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-ω²) dω = √π / 2
132K
5φ² + 6φ + 6 = 0
∫₀^∞ e^(-n²) dn = √π / 2
170K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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det| 9 4 ; 1 10 | = 86
344K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
393K
∑_{k=1}^{n} k = n(n+1)/2
130K
∑_{k=1}^{n} k = n(n+1)/2
82K