Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:23Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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det| 9 1 ; 7 10 | = 83
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det| 9 7 ; 3 10 | = 69
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∫₀^∞ e^(-n²) dn = √π / 2
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