Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 00:46Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
det| 2 9 ; 2 3 | = -12
∫₀^∞ e^(-n²) dn = √π / 2
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PV = nRT
\frac{7}{1} \sum_{i=1}^{n} i^{2}
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det| 7 4 ; 4 8 | = 40
344K
6n² + 5n + 7 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
346K
det| 3 8 ; 6 4 | = -36
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
130K
λ = h/p
d/dβ [β^12] = 12β^11
\frac{12}{3} \sum_{i=1}^{n} i^{2}
e^{i\pi} + 1 = 0