Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 06:40Z
∇²t = 0
det| 5 8 ; 6 6 | = -18
det| 7 4 ; 4 8 | = 40
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d/dy [y^12] = 12y^11
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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7γ² + 2γ + 5 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
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det| 3 8 ; 0 4 | = 12
∑_{k=1}^{n} k = n(n+1)/2
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