Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:37Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
97K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
2y² + 4y + 4 = 0
det| 9 4 ; 1 10 | = 86
393K
det| 5 9 ; 7 6 | = -33
346K
∑_{k=1}^{n} k = n(n+1)/2
130K