Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-09-30 19:50Z
2φ² + 3φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
199K
F = G m₁m₂ / r²
∑_{k=1}^{n} k = n(n+1)/2
313K
det| 9 2 ; 4 10 | = 82
191K
\lim_{z\to 0} \frac{\sin z}{z} = 1
CaCO₃ → CaO + CO₂
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2