Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-21 03:43Z
E = mc²
det| 4 9 ; 5 5 | = -25
det| 5 9 ; 7 6 | = -33
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E = mc²
det| 2 4 ; 6 3 | = -18
2r² + 5r + 7 = 0
det| 5 3 ; 3 6 | = 21
∇ × E = −∂B/∂t
AgNO₃ + NaCl → AgCl↓ + NaNO₃
11t² + 7t + 4 = 0
\lim_{β\to 0} \frac{\sin β}{β} = 1